| Nitro |
12-17-2018 11:55 AM |
Quote:
Originally Posted by Nitro
(Post 2407393)
R#2 - 1200M C4 (6F)T
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11-1-3 W/ 12-6-4
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12:00 AM EST
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Quote:
Originally Posted by Nitro
(Post 2407396)
6-12-3-4 Dutch Loss 40% Margin - Passed $52.00 Quinella & $1033.80 Triple Box / ALL of that one!
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Quote:
Originally Posted by ReplayRandall
(Post 2407407)
Nitro, do me a favor and show the bets you made and the total outlay you had in this race.....Thanks.
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Quote:
Originally Posted by Nitro
(Post 2407411)
Sure maybe tomorrow when I'm not so busy.
In the meantime you're pretty sharp. There's only 15 combos for a quinella box with 6 entries. So that's not too difficult to figure out. Right?
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Quote:
Originally Posted by ReplayRandall
(Post 2407414)
Of course, it's the tri's I'm working on....Thanks.
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Well, without going into a lot of detail illustrating how to use any one or more of the Key selections to create boxing permutations for a Triple bet I can simply say that the following could be done with a single Key that has to finish in the money:
3 / 11-1-12-6-4 / 11-1-12-6-4 = 5x4 = 20x$2=$40
11-1-12-6-4 / 3 / 11-1-12-6-4 = 5x4 = 20x$2=$40
11-1-12-6-4 / 11-1-12-6-4 / 3 = 5x4 = 20x$2=$40 / Total = $120.00
If you used all 3 Keys this way the Total would be $360.00. That would cover any combination with any one of the Keys finishing in the money.
If this method was used and more that one Key finished in the money, than the Triple would be hit more than once.
Of course, theres another quicker approach by just boxing all 6 selections:
11-1-3-12-6-4 = 6x5x4 = 120 permutations @ $2/ea = $240.00
The bottom line for executing these type of betting strategies would be based on the odds value of the selected entries. |
